\(- \sqrt{3}\)
\(-\frac{\sqrt{3}}{2}\)
\(\frac{\sqrt{3}}{2}\)
\(\sqrt{3}\)
Correct answer is A
\(\sin \theta = \frac{\sqrt{3}}{2} \implies opp = \sqrt{3}; hyp = 2\)
\(adj^{2} = 2^{2} - (\sqrt{3})^{2} = 1 \implies adj = 1\)
\(\cos \theta = \frac{1}{2}\)
\(\sin 2\theta = \sin (180 - \theta) = \sin \theta = \frac{\sqrt{3}}{2}\)
\(\cos 2\theta = \cos (180 - \theta) = -\cos \theta = -\frac{1}{2}\)
\(\tan 2\theta = \frac{\sin 2\theta}{\cos 2\theta} = \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}}\)
= \(- \sqrt{3}\)
Evaluate \(\int_{-2}^{3} (3x^{2} - 2x - 12) \mathrm {d} x\)...
The inverse of a function is given by \(f^{-1} : x \to \frac{x + 1}{4}\)....
If \(P = {x : -2 < x < 5}\) and \(Q = {x : -5 < x < 2}\) are subsets of \(\mu = {x : -5 ...
If \(y = 2(2x + \sqrt{x})^{2}\), find \(\frac{\mathrm d y}{\mathrm d x}\)....