9/16
81/16
9
9 \(\frac{9}{16}\)
Correct answer is D
GP : 36, P, \(\frac{q}{4}\), q, ... p + q = ?
| Recall, | common | ratio, | r | = | Tn
Tn-1 |
= | T2
T1 |
= | T3
T2 |
= | T4
T3 |
| ∴ | P
36 |
= | 9
4 |
÷ | p | ; | p\(^2\) | = | 9
4 |
x | 36 | ; | p\(^2\) | = | 81 |
| p | = | 9 | ∴ | r | = | T2
T1 |
= | 9
36 |
= | 1
4 |
| Also | r | = | T4
T3 |
= | q | ÷ | 9
4 |
∴ \(\frac{1}{4}\) = q ÷ \(\frac{9}{4}\) ;
\(\frac{9}{4}\) = 4q
| 16q | = | 9 | , | q | = | 9
16 |
∴ | p | + | q | = | 9 | + | 9
16 |
= | 9 | 9
16 |
Evaluate \(∫^0_{-1}\) (x + 1)(x - 2) dx
7/6
5/6
-5/6
-7/6
Correct answer is D
\(∫^0_{-1}\) (x + 1)(x - 2) dx
= \(∫^0_{-1}\) \(x^2 - x - 2\) dx
Integrated \(x^2 - x - 2\) = \(\frac{x^3}{3} - \frac{x^2}{2} -2\)
Which of the following is the semi-interquartile range of a distribution?
Mode - Median
Highest score - Lowest score
1/2 (Upper Quartile - Median)
1/2 (Upper Quartile - Lower Quartile)
Correct answer is D
"Semi" means "half"
Interquartile range = Upper quartile - Lower quartile
| Semi | interquartile | range | = | 1
2 |
( | upper | quartile | - | lower | quartile | ) |
2x + 3y + 6 = 0
3x - 2y - 6 = 0
-3x 2y - 6 = 0
-2x + 3y - 6 = 0
Correct answer is D
Recall:
| x
a |
+ | y
b |
=1 |
Where 'a' and 'b' are the x and y intercept respectively.
| x
-3 |
+ | y
2 |
=1 |
2x-3y = -6
2x - 3y + 6 = 0 -------(1)
multiply through by -1
-2x + 3y - 6 = 0
Express \(\frac{4π}{2}\) radians in degrees.
288º
200º
144º
120º
Correct answer is C
\(\frac{4π}{2}\) = \(\frac{4}{5} * 180\)
= 144º