x = -3 or -5
x = -3 or 5
x = 3 or -5
x = 3 or 5
Correct answer is C
f:x → 2x\(^2\) + 3x -7 and
g:x →5x\(^2\) + 7x - 6
If 3f(x) = g(x)
3(2x\(^2\) + 3x -7) = 5x\(^2\) + 7x - 6
6x\(^2\) + 9x - 21 = 5x\(^2\) + 7x - 6
6x\(^2\) - 5x\(^2\) + 9x - 7x - 21 + 6
x\(^2\) + 2x - 15 = 0
x = 3 or -5
All strong wrestlers are weightlifters
Some strong wrestlers are not weightlifters
Some weak wrestlers are weightlifters
All weightlifters are wrestlers
Correct answer is B
No explanation has been provided for this answer.
Simplify \(\frac{9*3^{n+1} - 3^{n+2}}{3^{n+1} - 3^{n}}\)
3
9
27
81
Correct answer is B
\(\frac{9*3^{n+1} - 3^{n+2}}{3^{n+1} - 3^{n}}\)
= \(\frac{3^n * 3^n * 3^1 * - 3^2 * 3^2}{3^n * 3^1 - 3^n}\)
= \(\frac{3^n (3^2 * 3^1)}{3^n (3^1 - 1)}\)
= \(\frac{27-9}{3-1}\)
= \(\frac{18}{2}\)
= 9
If \(log_{10}(3x+1) + log_{10}4 = log_{10}(9x+2)\), find the value of x
\(\frac{1}{3}\)
1
2
3
Correct answer is C
\(log_{10}(3x+1) + log_{10}4 = log_{10}(9x+2)\)
\(log_{10}4(3x+1) = log_{10}(9x+2)\)
4(3x+1) = 9x + 2
12x -4 = 9x + 2
12x - 9x = 2 + 4
3x = 6
x = 2
(\(\frac{3√6}{√5} + \frac{√54}{3√5}\))\(^{-1}\)
\(\frac{5√3}{6}\)
\(\frac{3√15}{6}\)
\(\frac{5√6}{12}\)
\(\frac{5√3}{12}\)
Correct answer is C
(\(\frac{3√6}{√5} + \frac{√54}{3√5}\))\(^{-1}\)
= \(\frac{√5(3√5)}{3√6 + 3√6}\)
= \(\frac{3*5}{6√6} = \frac{5}{2√6}\)
= \(\frac{5*2√6}{2√6+2√6} = \frac{10√6}{4*6}\)
= \(\frac{5√6}{12}\)