10.1 years
9.3 years
8.7 years
8 . 3 years
Correct answer is A
x = 10 ; 10 = \(\frac{x}{25}\)
x = 250
x = \(\frac{250 + 12.4}{26}\)
x = 10.09
x = 10.1 years
\(\sqrt{3 - 2}\)
2 - \(\sqrt{3}\)
\(\sqrt{3}\)
-2
Correct answer is C
Tan 60 = 3; Tan 30 = 1
\(\frac{\tan 60^o - 1}{1 - tan 30^o}\) = \(\frac{\sqrt{3 - 1}}{1 - \frac{1}{\sqrt{3}}}\) = \(\frac{\sqrt{3 - 1}}{\frac{3 - 1}{\sqrt{3}}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3 - 1}}{\sqrt{3}}\)
= \(\frac{\sqrt{3 - 1}}{1} \times \frac{\sqrt{3}}{\sqrt{3}}\)
= \(\sqrt{3}\)
A bearing of 320\(^o\) expressed as a compass bearing is
N 50\(^o\) W
N 40\(^o\) W
N 50\(^o\) E
N 40\(^o\) E
Correct answer is B
No explanation has been provided for this answer.
If P(2,3) and Q)2, 5) are points on a graph, calculate the length PQ
6 units
5 units
4 units
2 units
Correct answer is D
\(\sqrt{(x_2 - x_1)^2 + (y_2 - Y_1)^2}\)
= \(\sqrt{(2 - 2)^2 + (5 - 3)^2}\)
= \(\sqrt{0^2 + 2^2}\)
= \(\sqrt{4}\)
= 2 units
Calculate the gradient (slope) of the joining points (-1, 1) and (2, -2)
-1
\(\frac{-1}{2}\)
\(\frac{1}{2}\)
1
Correct answer is A
Gradient = m = \(\frac{y_2 - y_1}{x_2 - x_1}\)
= \(\frac{-2 -1}{2 + 1}\)
= \(\frac{-3}{3}\)
= -1