WAEC Past Questions and Answers - Page 2435

12,171.

Simplify; 3x - (p - x) - (r - p)

A.

2x - r

B.

2x + r

C.

4x - r

D.

2x - 2p - r

Correct answer is C

3x - (p - x) - ( r - p) = 3x - p + x - r + p = 4x - r

12,172.

Solve: - \(\frac{1}{4}\) < \(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\)

A.

-\(\frac{5}{9}\) < x <\(\frac{8}{9}\)

B.

-\(\frac{8}{9}\) < x <\(\frac{7}{9}\)

C.

-\(\frac{8}{9}\) < x <\(\frac{5}{9}\)

D.

-\(\frac{7}{9}\) < x <\(\frac{8}{9}\)

Correct answer is A

\(\frac{3}{4}\) (3x - 2) < \(\frac{1}{2}\); \(\frac{3}{4}\) (3x - 2) > - \(\frac{1}{4}\)

3(3x - 2) < 2; 3(3x - 2) > -1

9x - 6 < 2; 9x - 6 > -1

9x < 8; 9x > 5

x < \(\frac{5}{9}\); x > \(\frac{8}{9}\)

12,173.

One factor of \(7x^2 + 33x - 10\) is

A.

7x + 5

B.

x - 2

C.

7x - 2

D.

x - 5

Correct answer is C

\(7x^2 + 33x - 10\)

\(7x^2 + 35x - 2x - 10\)

7x (x + 5) - 2 (x + 5)

(7x - 2) (x + 5)

12,174.

A sum of N18,100 was shared among 5 boys and 4 girls with each boy taking N20.00 more than each girl. Find a boy's share.

A.

N1,820.00

B.

2,000.00

C.

N2,020.00

D.

N2,040.00

Correct answer is C

Let a girl's share = x + 20

4x + 5(x + 20) = 18,100

4x + 5x + 100 = 18,100

9x + 100 = 18,100

9x = 18,000

x = \(\frac{18,000}{9}\)

x = 2,000

\(\therefore\) Each boy gets N(2,000 + 20)

 = N2,020.

12,175.

Solve the equation: \(\frac{1}{5x} + \frac{1}{x}\)= 3

A.

\(\frac{1}{5}\)

B.

\(\frac{2}{5}\)

C.

\(\frac{3}{5}\)

D.

\(\frac{4}{5}\)

Correct answer is B

\(\frac{1}{5x} + \frac{1}{x}\)= 3

\(\frac{1 + 5}{5x}\) = 3

6 = 15x

x = \(\frac{6}{15}\)

= \(\frac{2}{5}\)