The values of x when y = 3 are approximately
-4.7 and 1.4
-4.6 and 1.5
-3.6 and 0.4
-3.6 and 1.5
Correct answer is B
No explanation has been provided for this answer.
Use the graph to answer the Question below
What are the roots of the equation x2 + 3x - 4 = 0?
1, 4
-1, -4
-1, 4
-4, 1
Correct answer is D
x2 + 3x – 4 = 0 has roots value at the curve makes touches with the x – axis. The curve contact is at x = -4 and +1.
The diagram is a circle centre O. Find the value of x
30o
50o
61o
78o
65.5\(^{\circ}\)
Correct answer is E
∠PQR (Reflex) = 360° – 68° = 292°
∠PQR = 2∠PQR
292° = 4x + 30°
4x = 292 – 30 = 262
\(x = \frac{262}{4}=65.5°\)
Simplify \(\frac{2}{a+b}-\frac{1}{a-b}\)
\(\frac{3}{a+b}\)
\(\frac{a-3b}{a^2-b^2}\)
\(\frac{3a-b}{a^2 – b^2}\)
\(\frac{a-3b}{a^2+b^2}\)
Correct answer is B
Simplify \(\frac{2}{a+b}-\frac{1}{a-b}; \frac{2(a-b)-1(a+b)}{(a+b)(a-b)}\)
= \(\frac{2a-2b-a-b}{(a+b)(a-b)}\)
= \(\frac{a-3b}{a^2 - ab + ab - b^2}\)
= \(\frac{a-3b}{a^2-b^2}\)
A boy walks 800m in 20 minutes. Calculate his average speed in km per hour
2.4
4
16
24
Correct answer is A
\(Average \hspace{1mm}speed = \frac{Distance}{Time\hspace{1mm} taken}\\
Distance = 800m = \frac{800}{1000}km = 0.8km\\
Time\hspace{1mm}taken = 20\hspace{1mm}minutes = \frac{20}{60}hr=\frac{1}{3}hr\\Average \hspace{1mm} speed = \left(0.8\div \frac{1}{3}\right)km/hr = (0.8\times3)km/hr\\=2.4km/hr\)
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