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VIP = 80, Regular = 100
VIP = 60, Regular = 120
VIP = 60, Regular = 100
VIP = 80, Regular = 120
Correct answer is D
Let \(x\) = number of VIP tickets sold and
\(y\) = number of regular tickets sold
Total number of tickets sold = 200
⇒ \(x\) + \(y\) = 200 ---- (i)
If it costs ₦1,200 for a VIP ticket, then it costs ₦1200x for \(x\) number of VIP tickets sold and
If it costs ₦700 for a regular ticket, then it costs ₦700\(y\) for \(y\) number of VIP tickets sold
The total amount realised from the sale of tickets = ₦180,000
⇒ 1200\(x\) + 700\(y\) = 180000 ----- (ii)
From equation (i)
\(x\) = 200 - \(y\) ----- (iii)
Substitute (200 - \(y\)) for \(x\) in equation (ii)
⇒ 1200(200 - \(y\)) + 700\(y\) = 180000
⇒ 240000 - 1200\(y\) + 700\(y\) = 180000
⇒ 240000 - 500\(y\) = 180000
Collect like terms
⇒ 240000 - 180000 = 500\(y\)
⇒ 60000 = 500\(y\)
⇒ \(y = \frac{60000}{500} = 120\)
Substitute 120 for \(y\) in equation (iii)
⇒ \(x = 200 - 120\)
⇒ \(x = 80\)
∴ The total number of VIP tickets sold is 80 and regular is 120
16 cm
8 cm
5 cm
10 cm
Correct answer is D
|AP| = |PB| = \(x\) (The perpendicular to a chord bisects the chord if drawn from the center of the circle.)
From ∆OPB
Using Pythagoras theorem
⇒ \(13^2 = 12^2 + x^2\)
⇒ \(169 = 144 + x^2\)
⇒ \(169 - 144 = x^2\)
⇒ \(x^2 = 25\)
⇒ \(x = \sqrt25 = 5 cm\)
∴ Length of the chord |AB| = \(x + x = 5 + 5 = 10 cm\)
θ = 223\(^o\), 305\(^o\)
θ = 210\(^o\), 330\(^o\)
θ = 185\(^o\), 345\(^o\)
θ = 218\(^o\), 323\(^o\)
Correct answer is D
On the \(y\)-axis, each box is \(\frac{1 - 0}{5} = \frac{1}{5}\) = 0.2unit
On the \(x\)-axis, each box is \(\frac{90 - 0}{6} = \frac{90}{6} = 15^o\)
⇒ \(θ_1 = 180^o + (2.5\times15^o) = 180^o + 37.5^o = 217.5^o ≃ 218^o \)(2 and half boxes were counted to the right of 180\(^o\))
⇒ \(θ_2 = 270^o + (3.5\times15^o) = 270^o + 52.5^o = 322.5^o ≃ 323^o \)(3 and half boxes were counted to the right of 270\(^o\))
∴ \(θ = 218^o, 323^o\)
62 km
97 km
389 km
931 km
Correct answer is A
AB = \(\frac{θ}{360}\times 2\pi Rcos\propto\) (distance on small circle)
= 64 - 56 = 8\(^o\)
\(\propto = 86^o\)
⇒ AB = \(\frac{8}{360}\) x 2 x 3.142 x 6370 x cos 86
⇒ AB = \(\frac{22,338.29974}{360}\)
∴ AB = 62km (to the nearest km)
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