How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Solve the given equation \((\log_{3} x)^{2} - 6(\log_{3} x) + 9 = 0\)
27
9
\(\frac{1}{27}\)
18
81
Correct answer is A
\((\log_{3} x)^{2} - 6(\log_{3} x) + 9 = 0\)
Let \(\log_{3} x = a\).
\(a^{2} - 6a + 9 = 0\)
\(a^{2} - 3a - 3a + 9 = 0\)
\(a(a - 3) - 3(a - 3) = 0\)
\((a - 3)(a - 3) = 0\)
\(\implies a = 3 (twice)\)
\(\log_{3} x = 3 \implies x = 3^{3} = 27\)
x + 8x2 - 5 = 0
2x2 - 5x + 8 = 0
2x2 - 8x + 5 = 0
x2 + 8x - 5 = 0
Correct answer is B
x2 - (sum of roots) x + (product of roots) = 0
x2 - \(\frac{5x}{2}\) + 4 = 0
2x2 - 5x + 8 = 0
What is the size of an exterior angle of a regular pentagon?
36o
60o
72o
120o
360o
Correct answer is C
Pentagon is a polygon with 5 sides. Sum of interior angles of polygon (regular) = (2n - 4) x 90o
= 5
= (10 - 4) x 90o
= 540o
each interior angle = \(\frac{540}{5}\)
= 108o
= 180o let x represent ext. angle
x + 108o = 180v
x = 180o - 108o
= 72o
The difference between 4\(\frac{5}{7}\) and 2\(\frac{1}{4}\) greater by
\(\frac{23}{28}\)
\(\frac{24}{28}\)
\(\frac{50}{56}\)
\(\frac{27}{28}\)
\(\frac{48}{56}\)
Correct answer is C
Difference between 4\(\frac{5}{7}\) and 2\(\frac{1}{4}\)
\(\frac{33}{7}\) - \(\frac{9}{4}\) = \(\frac{69}{24}\)
The sum of \(\frac{1}{14}\) and 1\(\frac{1}{14}\) + \(\frac{3}{2}\)
= \(\frac{11}{7}\)
\(\frac{69}{28}\) - \(\frac{11}{7}\) = \(\frac{25}{28}\)
= \(\frac{50}{56}\)
12.25kg
6.75kg
8.75kg
15.75kg
8.25kg
Correct answer is C
Sugar : flour = 2.5 : 4.5
Total = 7
sugar used = \(\frac{2.5}{7}\) x 24.5
= \(\frac{61.25}{7}\)
= 8.75