How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{2P}{\pi}\)
\(\frac{P}{\sqrt{\pi}}\)
\(\frac{P}{\sqrt{2\pi}}\)
2\(\frac{P}{\pi}\)
Correct answer is D
Surface area of a sphere = 4\(\pi\)r2
\(\frac{1}{16}\) of 4\(\pi\)r2
= \(\frac{\pi r^2}{4}\)
P = \(\frac{\pi r^2}{4}\)
r = 2\(\frac{P}{\pi}\)
25cm
18cm
15cm
24cm
27cm
Correct answer is C
Area = L x B
L - B = 6
L = 6 + B
area = 135
B(6 + B) = B2 + 6B - 135 = 0
B = 9
L = 6 + 9
= 15
1.0622
10.6225
0.1328
0.3218
2.0132
Correct answer is C
\(4t^{2} + 7t - 1 = 0\)
Using a = 4, b = 7, c = -1.
\(x = \frac{-b \pm \sqrt{b^{2} - 4ac}}{2a}\)
= \(\frac{-7 \pm \sqrt{7^{2} - 4(4)(-1)}}{2(4)}\)
= \(\frac{-7 \pm \sqrt{49 + 16}}{8}\)
= \(\frac{-7 \pm \sqrt{65}}{8}\)
= \(\frac{-7 \pm 8.0623}{8}\)
The positive answer = \(\frac{-7 + 8.0623}{8} = \frac{1.0623}{8}\)
\(\approxeq 0.1328\) (4 decimal place)
Evaluate \(\frac{6.3 \times 10^5}{8.1 \times 10^3}\) to 3 significant fiqures
77.80
778.0
7.870
8.770
88.70
Correct answer is A
\(\frac{6.3 \times 10^5}{8.1 \times 10^3}\)
\(\frac{7}{9} \times 10^{2}\)
= \(0.77778 \times 10^{2}\)
= \(77.778 \approxeq 77.80\)
10011
111011
111000
11001
110011
Correct answer is D
\(\begin{array}{c|c} 2 & 25\\2 & 12 R 1\\2 & 6 R 0\\2 & 3 R 0\\2 & 1 R 1\end{array}\)
= (11001)