Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

316.

Find the equation of the line parallel to 2y = 3(x - 2) and passes through the point (2, 3) 

A.

y = \(\frac{2}{3} x - 3\)

B.

y = \(\frac{2}{3} x - 2\)

C.

y = \(\frac{2}{3} x\)

D.

y = \(\frac{-2}{3} x\)

Correct answer is C

2y = 3(x - 2)

\(\frac{2y}{2} = \frac{3x}{2} - \frac{6}{2}\)

y = \(\frac{3}{2}x - 3\)

m = \(\frac{3}{2}\)

\(\frac{y - y_1}{x - x_1}\) = m

\(\frac{y - 3}{x - 2} = \frac{3}{2}\)

2y - 6 = 3x - 6

\(\frac{2y}{2} = \frac{3x}{2}\) 

y = \(\frac{3}{2}\)x

317.

In the diagram, PQ // SR. Find the value of x

A.

34

B.

46

C.

57

D.

68

Correct answer is B

x + 68\(^o\)  + 246\(^o\) = 360\(^o\)

x + 314\(^o\) = 360\(^o\)

x = 360\(^o\) - 314\(^o\)

x = 46\(^o\)

318.

A solid cuboid has a length of 7 cm, a width of 5 cm, and a height of 4 cm. Calculate its total surface area.

A.

280 cm\(^2\)

B.

166 cm\(^2\)

C.

140 cm\(^2\)

D.

83 cm\(^2\)

Correct answer is B

Total = 2(LB + BH + LH) 

Surface area 

= 2(7 x 5 + 5 x 4 + 7 x 4)

= 2(35 + 20 + 28)

= 2(83) 

= 166cm\(^2\) 

319.

Two buses start from the same station at 9.00am and travel in opposite directions along the same straight road. The first bus travel at a speed of 72 km/h and the second at 48 km/h. At what time will they be 240km apart?

A.

1:00 pm

B.

12:00 noon

C.

11:00 am

D.

10:00 am

Correct answer is C

Let x be the time 

Then 72x + 48x = 240 

\(\frac{120}{120} \times \frac{240}{120}\)

x = 2hrs

9:00 + 2hrs = 11:00 am 

320.

Given that x is directly proportional to y and inversely proportional to Z, x = 15 when y = 10 and Z = 4, find the equation connecting x, y and z

A.

x = \(\frac{6y}{z}\)

B.

x = \(\frac{12y}{z}\)

C.

x = \(\frac{3y}{z}\)

D.

x = \(\frac{3y}{2z}\)

Correct answer is A

\(x\) x \(\frac{y}{z}\) 

x = \(\frac{ky}{z}\)

15 = \(\frac{10k}{4}\) 

 \(\frac{60}{10}\) = k = 6

Therefore; x = \(\frac{6y}{z}\)