How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Solve 3x - 2y = 10 and x + 3y = 7 simultaneously
x = -4 and y = 1
x = -1 and y = -4
x = 1 and y = 4
x = 4 and y = 1
Correct answer is D
3x - 2y = 10 - - x 3
x + 3y = 7 ---x 2
------------------------
9x - 6y = 30
2x + 6y = 14
-------------------------
\(\frac{11x}{11} \frac{44}{11}\)
x = 4
From x + 3y = 7
3y = 7 - 4
\(\frac{3y}{3}\) = \(\frac{3}{3}\)
y = 1
If x = 3 and y = -1, evaluate 2(x\(^2\) - y\(^2\))
24
22
20
16
Correct answer is D
2(\(x^2 - y^2\))
= 2(x + y)(x - y)
= 2(3 + (-1))(3 - (-1))
= 2(2)(4) = 16
Given that \(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\) = x + y\(\sqrt{15}\), find the value of (x + y)
1\(\frac{3}{5}\)
1\(\frac{2}{5}\)
1\(\frac{1}{5}\)
\(\frac{1}{5}\)
Correct answer is C
\(\frac{\sqrt{3} + \sqrt{5}}{\sqrt{5}}\) = x + y\(\sqrt{15}\)
cross multiply to have: \(\sqrt{3}\) + \(\sqrt{5}\) = x\(\sqrt{5}\) + 5y\(\sqrt{3}\)
Collect like roots : x\(\sqrt{5}\) = \(\sqrt{5}\) → x = 1
5y\(\sqrt{3}\) = \(\sqrt{3}\) → y = \(\frac{1}{5}\)
∴ ( x + y ) = 1 + \(\frac{1}{5}\)
= 1\(\frac{1}{5}\)
N470,000.00
N480,000.00
N490,000.00
N500,000.00
Correct answer is D
S.I = \(\frac{x \times 2 \times 5}{100}\) = 0.1x
A = P + S.I
550,000 = x + 0.1x
\(\frac{550,000}{1.1} = \frac{1.1x}{1.1}\)
x = N500,000
If 101\(_{\text{two}}\) + 12y = 3.3\(_{\text{five}}\). Find the value of y
8
7
6
5
Correct answer is C
012 + 01 = 01
101\(_2\) + 12\(_y\) = 2.3\(_5\)
1 x 2\(^o\) + 0 x 2\(^o\) + 1 x2\(^2\) + 1 x y\(^o\) + 2 x y\(^1\) = 3 x 5\(^o\) + 3 x 5\(^1\)
1 + 4 + 1 + 2y = 3 + 15
6 + 2y = 18
2y = 18 - 6
\(\frac{2y}{2} = \frac{12}{2}\)
y = 6