How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the quadratic equation whose roots are \(\frac{1}{2}\) and -\(\frac{1}{3}\)
3x\(^2\) + x + 1 = 0
6x\(^2\) + x - 1 = 0
3x\(^2\) + x - 1 = 0
6x\(^2\) - x - 1 = 0
Correct answer is D
x = \(\frac{1}{2}\) and x = \(\frac{-1}{3}\)
(2x - 1) = 0 and (3x + 1) = 0
(2x - 1) (3x + 1) = 0
6x\(^2\) - x - 1 = 0
Make m the subject of the relation k = \(\frac{m - y}{m + 1}\)
m = \(\frac{y + k^2}{k^2 + 1}\)
m = \(\frac{y + k^2}{1 - k^2}\)
m = \(\frac{y - k^2}{k^2 + 1}\)
m = \(\frac{y - k^2}{1 - k^2}\)
Correct answer is B
k = \(\frac{m - y}{m + 1}\)
k\(^2\) = \(\frac{m - y}{m + 1}\)
k\(^2\)m + k\(^2\) = m - y
k\(^2\) + y = m - k\(^2\)m
\(\frac{k^2 + y}{1 - k^2}\) = m\(\frac{(1 - k^2)}{1 - k^2}\)
m = \(\frac{y + k^2}{1 - k^2}\)
Solve \(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
x > \(\frac{7}{22}\)
x < \(\frac{7}{22}\)
x > \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)
Correct answer is D
\(\frac{1}{3}\)(5 - 3x) < \(\frac{2}{5}\)(3 - 7x)
5(5 - 3x) < 6(3 - 7x)
25 - 15x < 18 - 42x
- 15x + 42x < 18 - 25
\(\frac{27x}{27}\) < \(\frac{-7}{27}\)
x < \(\frac{-7}{27}\)
The first term of a geometric progression (G.P) is 3 and the 5th term is 48. Find the common ratio.
2
4
8
16
Correct answer is A
T\(_5\) = ar\(^4\)
\(\frac{48}{3} = \frac{3r^4}{3}\)
16 = r\(^4\)
r = \(4\sqrt{16}\)
= 2
~ y \(\to\) ~ x
y \(\to\) ~ x
~ x \(\to\) ~ y
y \(\to\) x
Correct answer is C
No explanation has been provided for this answer.