WAEC Past Questions and Answers - Page 1172

5,856.

If \(s = 3i - j\) and \(t = 2i + 3j\), find \((t - 3s).(t + 3s)\).

A.

-77

B.

-71

C.

-53

D.

-41

Correct answer is A

\(s = 3i - j; t = 2i + 3j\)

\( t - 3s = (2i + 3j) - 3(3i - j) = 2i + 3j - 9i + 3j = -7i + 6j\)

\(t + 3s = (2i + 3j) + 3(3i - j) = 2i + 3j + 9i - 3j = 11i\)

\((t - 3s).(t + 3s) = (-7i + 6j).(11i) = -77\)

5,857.

A particle is acted upon by two forces 6N and 3N inclined at an angle of 120° to each other. Find the magnitude of the resultant force.

A.

\(18\sqrt{3}\) N

B.

\(27\) N

C.

\(24\) N

D.

\(3\sqrt{3}\) N

Correct answer is D

No explanation has been provided for this answer.

5,858.

Where goods are invoiced by a firm its branch at cost-plus, the branch stock adjustment accounts is used to determine

A.

Cost price

B.

Branch profit

C.

Selling price

D.

Branch expenses

Correct answer is A

No explanation has been provided for this answer.

5,859.

The equation of a circle is \(x^{2} + y^{2} - 8x + 9y + 15 = 0\). Find its radius.

A.

5

B.

\(\frac{1}{2}\sqrt{15}\)

C.

\(\frac{1}{2}\sqrt{85}\)

D.

\(\sqrt{85}\)

Correct answer is C

The equation of a circle is given as \((x - a)^{2} + (y - b)^{2} = r^{2}\).

Expanding, we have: \(x^{2} - 2ax + a^{2} + y^{2} - 2by + b^{2} = r^{2}\)

\(x^{2} + y^{2} - 2ax - 2by + a^{2} + b^{2} = r^{2}\)

Comparing with the equation, \(x^{2} + y^{2} - 8x + 9y = -15\), we have

\(2a = 8; 2b = -9; r^{2} - a^{2} - b^{2} = -15\)

\(a = 4; b = \frac{-9}{2}\)

\(\therefore  r^{2} = -15 + 4^{2} + (\frac{-9}{2})^{2}\)

= \(-15 + 16 + \frac{81}{4} = \frac{85}{4}\)

\(r = \sqrt{\frac{85}{4} = \frac{1}{2}\sqrt{85}\)

5,860.

Two bodies of masses 3kg and 5kg moving with velocities 2 m/s and V m/s respectively in opposite directions collide. If they move together after collision with velocity 3.5 m/s in the direction of the 5kg mass, find the value of V.

A.

7.8 m/s

B.

6.8 m/s

C.

5.6 m/s

D.

4.6 m/s

Correct answer is B

Since the bodies are in an opposite direction, one takes the negative velocity.

\(m_{1}v_{1} + m_{2}v_{2} = (m_{1} + m_{2})v\) (Momentum when the two bodies move in the same direction after collision)

\(3(-2) + 5(V) = (3 + 5)3.5\)

\(-6 + 5V = 28 \implies 5V = 34; V = 6.8 m/s\)